A 16-bar song might have up to 6,000 notes, making it one of the most widely known patterns. It is made in 12-note or 16-note ways with the 8th, 9th, 10th and 12th notes.
So how many notes does it take to play one bar?
As in the piano pattern, there are 4 types of notes with 4 types of notes from each one. The main difference is the number of notes in a bar. A bar contains 12 notes:
An octave, or 12 notes from A to G for a total of 160 bits.
For an octave, each note has an octave of 3, giving you 48 notes altogether.
There are 2nd, 4th and 6th notes for a total of 8 bits.
If you have a piano or instrument and want to find out how many bits each note is, use this simple calculation:
Where m is the note number, e is the octave (12×2), and b is the number of bits required to hold the note.
What is the root of 16?
The root of 16 is 16 (or 2) times 10. So, the root of 16 is 16*10. In other words, we have 10 = 16*32.
Now for some fun math.
The root of an octave 16-note scale is 15, which is 10×2. So, 15 = 16*32.
The root of a 16-note scale from A to C is 22, which is 5×2. So, 22 = 16*32.
The root of a 16-note scale from D to E is 24, which is 3×2. So, 24 = 16*32.
The root of a 16-note scale from F to G is 30, which is 8×2. So, 30 = 16*32.
And the root of a 16-note scale from H to J is 46, which is 16×4. So, 46 = 16*32.
So, we get the first four roots: the root of 16 and the root of 16 times the number of bits required to hold each note. So, 16 = 24×96 = 6,288,144, which is 26,576,824, which is 9.14 billion.
Which is the smallest number of bits?
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